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3 years ago

10

What is 47/20 written as a decimale

1 answer:

Lelechka [254]3 years ago

8 0

Answer:

2.35

Step-by-step explanation:

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How many fourths are in one half? Please help me I'm confusion jk I'm confused thanks lol

RSB [31]

1/4 + 1/4= 1/2

There are 2/4 in 1/2.

Hope this helps! :)

6 0

4 years ago

1.6y+y-4/15y+1 1/6y=2 1/3

Advocard [28]

<u>1.6y+y-4/15y+7/6y=21/3</u>

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<u>We move all terms to the left:</u>

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<u>1.6y+y-4/15y+7/6y-(21/3)=0</u>

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<u>Domain of the equation: 15y!=0</u>

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<u>y!=0/15</u>

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<u>y!=0</u>

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<u>y∈R</u>

<u>Domain of the equation: 6y!=0</u>

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<u>y!=0/6</u>

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<u>y!=0</u>

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<u>y∈R</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>1.6y+y-4/15y+7/6y-7=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>2.6y-4/15y+7/6y-7=0</u>

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<u>We calculate fractions</u>

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<u>2.6y+(-24y)/90y^2+105y/90y^2-7=0</u>

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<u>We multiply all the terms by the denominator</u>

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<u>(2.6y)*90y^2+(-24y)+105y-7*90y^2=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0</u>

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<u>Wy multiply elements</u>

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<u>-630y^2+105y+(+2.6y)*90y^2+(-24y)=0</u>

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<u>We get rid of parentheses</u>

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<u>-630y^2+105y+(+2.6y)*90y^2-24y=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>-630y^2+81y+(+2.6y)*90y^2=0</u>

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<u>Hoped this helped :)</u>

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%

Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

$I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx$

Replace $x \to x^{\frac1\phi} = x^{\phi-1}$ :

$I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx$

Split the integral at x = 1. For the integral over [1, ∞), substitute $x \to \frac1x$ :

$\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx$

The integrals involving tan⁻¹ disappear, and we're left with

$I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}$

8 0

2 years ago

it takes 70 oz of grass seed to seed 2800ft of lawn. at this rate, how much would be needed for 3600 ft of lawn?

Rom4ik [11]

Find the multiplier to get from 2800ft to 3600ft. Multiply the weight of seed required for 2800ft by this multiplier for your answer.
3600/2800=9/7
70*9/7=90 oz

4 0

3 years ago

What number must be added to the expression below to complete the square?

stiv31 [10]

D. 1/4

Explanation:

a perfect square is written in the form

$(x+a)^2 = x^2 + 2ax +a^2$ (1)

In our problem, we have this perfect square:

$x^2 - x + C$ (2)

with C being unknown. However, by comparing (1) and (2), we know that

$2a=-1$

So, we find

$a=-\frac{1}{2}$

and therefore, the missing term must be

$a^2 = \frac{1}{4}$

so the complete square is

$x^2 -x +\frac{1}{4}$

7 0

3 years ago

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