Well, is just their difference, let's first convert the mixed fraction to "improper" and then subtract.

$\bf \stackrel{mixed}{1\frac{1}{8}}\implies \cfrac{1\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{9}{8}}\\\\
-------------------------------\\\\
\cfrac{9}{8}-\cfrac{3}{4}\impliedby \textit{our LCD is then 8}\implies \cfrac{(1\cdot 9)~~-~~(2\cdot 3)}{8}
\\\\\\
\cfrac{9-6}{8}\implies \cfrac{3}{8}$

8 0

2 years ago

Heyy pls help! worth 20 points, and please only help if you know the answer. also no links those r kinda annoying lol

iragen [17]

Step 1: Find the slope:

$m= \dfrac{y_2-y_1}{x_2-x_1}= \dfrac{-2-7}{4-(-2)} = \dfrac{-9}{6}= -\dfrac{3}{2}$

This gives you $y=-\dfrac{3}{2}x+b$ , but we need to find b.

To find b, substitute in one (x,y) pair and it doesn't matter which one. I'll go with (4,-2):

$\begin{aligned}-2&=-\dfrac{3}{2}(4)+b\\[0.5em]-2&=-6+b\\[0.5em]4&=b\end{aligned}$

Now take that b-value and plug in into the slope-intercept form:

$y=-\dfrac{3}{2}x+4$

It's always a good idea to toss in the other x-value from the other point, to make sure it checks out.

7 0

2 years ago