So let's see here...
6:00 A.M. temperature is 33°F.
12:00 P.M temperature increased by 10°F making it 43°F.
3:00 P.M. temperature increased by another 12°F making it 55°F.
At 10:00 P.M it would decrease by 15°F making it 40°F.
The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F
Hope this helped!
Password to what exactly?
To do that you'll need the mean and standard deviation of all the scores. Can you provide this info?
For example: Supposing that the mean of these scores were 52 and the standard deviation 3. You'd need to find the "z-score" of 57 in this case.
57 - 52
It is z = ------------ , or z = 5/3, or z = 1.67.
3
Find the area to the left of z = 1.67. Multiply that area by 100% to find the percentile rank of the score 57.
The answer is 54.609 is less than 54.69
9514 1404 393
Answer:
∠Q = 89°
∠R = 123°
∠S = 91°
Step-by-step explanation:
It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.
arc QRS = 2·∠P = 114°
So, ...
arc QR = arc QRS - arc RS = 114° -41° = 73°
The total of the arcs around the circle is 360°, so ...
arc PQ = 360° -arc PS -arc QRS
arc PQ = 360° -137° -114° = 109°
__
∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)
∠Q = 89°
__
∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)
∠R = 123°
__
∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)
∠S = 91°
