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3 years ago

Select the property that allows the left member of the equation to be changed to the right member.

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

8 0

Identity
^^^^^^^^^^^^

KATRIN_1 [288]3 years ago

5 0

Answer: The correct option is

(7) Identity - addition.

Step-by-step explanation: We are given to select the property that allows the left member of the equation to be changed to the right member.

8 + 0 = 8.

We now that

if a is a real number, then the equation a + 0 = a is the additive identity.

Putting a = 8, we get

$8+0=8.$

Thus, the required property is additive identity.

Option (7) is CORRECT.

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Ratio =240cm to 400cm

Vanyuwa [196]

Answer:

I think it's 3:5

Step-by-step explanation:

I really don't understand your question

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2 years ago

382 3/10 - 191 87/100= math difficulties please answer this question

prohojiy [21]

3/10 = .3 and 87/100 = .87
382.3 - 191.87= 190.43
so the answer is 190.43

Hope this helped!! :))

7 0

3 years ago

Jarvis invested some money at 6% interest. Jarvis also invested $58 more than 3 times that amount at 9%. How much is invested at

DerKrebs [107]

9514 1404 393

Answer:

$3309 at 6%
$9985 at 9%

Step-by-step explanation:

Let x and y represent amounts invested at 6% and 9%, respectively.

y = 3x +58 . . . . . . . the amount invested at 9%

0.06x +0.09y = 1097.19 . . . . . . total interest earned

Substituting for y, we have ...

0.06x +0.09(3x +58) = 1097.19

0.33x + 5.22 = 1097.19 . . . . . . . . . simplify

0.33x = 1091.97 . . . . . . . . . . . . subtract 5.22

x = 3309 . . . . . . . . . . . . . . . . divide by 0.33

y = 3(3309) +58 = 9985

$3309 is invested at 6%; $9985 is invested at 9%.

8 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago

Need help can’t get this question wrong. Am I doing this right. And how would I write this. When I get the answer. Very confused

olya-2409 [2.1K]

Please show the question you’re confused about. We can’t help if we don’t know the problem :)

5 0

3 years ago