I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
i thinks its B thats what i put but im not sure , i havent got the paper back yet
Step-by-step explanation:
Y=2x-10
Y=4x-8
U substitute it and it turns into 2x-10 =4x-8
U get x=-1
Y=4*(-1)-8
Y=-12
(x,y)= (-1,-12)
If u have a phone u can use photo math or if u don’t there’s a thing called mathpapa
To find the amount of fabric for one side of the purse you will find the area of the trapezoidal space that is created. The latch is on the top, so the 2 in is not necessary information.
A = 1/2 h(b1 + b2)
1/2 x 13 x (10 + 16)
A = 169 square inches of fabric will be needed.
