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pochemuha
3 years ago
13

For any integer x, x^2-x will always produce an even value. True or false

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

That true. You have two ways to show it:

Method 1:

Factor the expression. You have

x^2-x = x(x-1)

So, you're multiplying two consecutive numbers. One of them must be even, and if a factor of a product is even, the result will be even.

Method 2:

If x is even, x^2 is even as well. So, x^2-x is a subtraction between even numbers, which gives an even number.

If x is odd, x^2 is odd as well. So, x^2-x is a subtraction between odd numbers, which gives an even number.

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1/100 is equal to 7/x
ella [17]
1/100 = 7/x
x = 7*100
x = 700

So, your final answer is 700

Hope this helps!
6 0
3 years ago
A line segment BK is an angle bisector of ΔABC. A line KM intersects side BC such, that BM = MK. Prove: KM ∥ AB.
weqwewe [10]

Answer:

∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK  and lies between AB and KM and BK is the transversal line)

m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)

Step-by-step explanation:

Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK

TO prove: KM ║AB

Now, As given in figure 1,

In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)

Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)

Now ∵ ∠MBK = ∠BKM

and  ∠ABK = ∠KBM

∴ ∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)

Hence proved.  

8 0
3 years ago
Read 2 more answers
For the love of God help me !! I'm desperate for it tomorrow
USPshnik [31]
D:5x-2>0 \wedge x>0 \wedge x-1>0\\D:5x>2 \wedge x>0 \wedge x>1\\D: x>\frac{2}{5} \wedge x>1\\D:x>1\\\log_2(5x-2)-\log_2x-\log_2(x-1)=2\\\log_2\frac{5x-2}{x(x-1)}=\log_24\\\frac{5x-2}{x(x-1)}=4\\4x(x-1)=5x-2\\4x^2-4x=5x-2\\4x^2-9x+2=0\\4x^2-x-8x+2=0\\x(4x-1)-2(4x-1)=0\\(x-2)(4x-1)=0\\x=2 \vee x=\frac{1}{4}\\\frac{1}{4}\not \in D \Rightarrow \boxed{x=2}
8 0
3 years ago
Read 2 more answers
The radius of the base of the cylinder is 2x cm and the height of the cylinder is h cm.
valentina_108 [34]

Answer:

h = 9x

Step-by-step explanation:

Given: i. for the cylinder, base radius = 2x cm, height = h cm

           ii. for the sphere, radius = 3x cm

           iii.  volume of the cylinder = volume of the sphere

volume of a cylinder is given as;

volume = \frac{1}{3}\pir^{2}h

where: r is its base radius and h the height

volume of the given cylinder = \frac{1}{3}\pi x (2x)^{2} x h

                                              = \frac{1}{3}\pi x 4x^{2} x h

                                              = \frac{4}{3}\pix^{2} h

volume of a sphere = \frac{4}{3}\pir^{3}

where r is the radius.

volume of the given sphere =  \frac{4}{3}\pi x (3x)^{3}

                                         =  \frac{4}{3}\pi x 9 x^{3}

                                         = 12\pix^{3}

Since,

volume of the cylinder = volume of the sphere

Then we have;

\frac{4}{3}\pix^{2} h = 12\pix^{3}

4\pix^{2} h = 36\pix^{3}

subtract x^{2} from both sides

4\pih = 36\pix

divide both sides by 4\pi

h = \frac{36\pi x}{4\pi }

  = 9x

h = 9x

5 0
2 years ago
I need help with this I have no idea how to do it
Lapatulllka [165]

Answer:

1. 62

2. 28

3. 56

4. 92

5. 21

6. 5

7. 38

8. 28

8 0
3 years ago
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