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Crazy boy [7]
3 years ago
11

The dot plots show the number of hours a group of fifth graders and seventh graders spent playing outdoors over a one-week perio

d.
Time Spent Playing Outdoors
for Fifth Graders and Seventh Graders
2 dot plots with number lines going from 0 to 10. A dot plot titled fifth grade has 0 dots above 0, 2 above 1, 3 above 2, 1 above 3, 4 above 4, 5 above 5, 5 above 6, 2 above 7, 2 above 8, and 0 and 9 and 10. A dot plot titled seventh grade has 2 dots above 0, 2 above 1, 3 above 2, 5 above 3, 5 above 4, 3 above 5, 3 above 6, 1 above 7, and 0 above 8, 9, and 10.

Which statement correctly compares the shape of the data in the plots?
Both sets of data have a peak at 5 hours and 6 hours.
In the seventh-grade data, the left side of the data looks similar to the right side, but not in the fifth-grade data.
In both sets, the data cluster around 3 hours.
There is a gap in the seventh-grade data, but not in the fifth-grade data.
Mathematics
1 answer:
Simora [160]3 years ago
3 0
Sui Sui Sui Sui Sui Sui Sui
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A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.
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Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- |E\ n\ B|

- |B|

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

B = \{6\}

E = \{2,4,6\}

Calculating the size of |E n B|

|E n B| = \{2,4,6\}\ n\ \{6\}

|E n B| = \{2,4,6\}

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

B = \{6\}

<em>The size = 1 because it contains 1 possible outcome</em>

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A triangle has side lengths of 15, 20, and 25. What type of triangle is it?
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2.Solve the following quadratic equations<br> i. 9x^2 - 1/16<br> ii. 2h^2 - 3h - 27
Juli2301 [7.4K]
i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}


ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\&#10;\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}

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Solve the system if possible by using Cramer's rule. If Cramer's rule does not apply, solve the system by using another method.
maks197457 [2]

Answer:

D = 0 , Dx = 4 , Dy = -6 , Dz = 2

Step-by-step explanation:

As per<u> cramer's rule</u>,

D = |   7    6    4  |  = 0

      |   3    3    3  |

      |   4    4    4  |

Dx =  |  10    6    4  | = 4

        |   1    3    3    |

        |   2    4    4   |

Dy = |   7    10    4  | = -6

       |   3    1     3   |

       |   4    2    4   |

Dz =  |  7    6    10 | = 2

        |   3    3    1   |

        |   4    4    2  |

   

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