The answer is c. 0.10. Week 4 is plotted at 0.35 and Week 2 is plotted at 0.25. Difference means subtract. 0.35 - 0.25 = 0.10. Hope this helps!
Answer:
Option C. 
Step-by-step explanation:
we know that
![A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7BP%5B%281%2Br%29%5E%7Bn%7D%20-1%5D%7D%7Br%281%2Br%29%5E%7Bn%7D%7D)
we have
substitute in the formula
![A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B400%5B%281%2B0.00625%29%5E%7B72%7D%20-1%5D%7D%7B0.00625%281%2B0.00625%29%5E%7B72%7D%7D%5C%5C%20%5C%5CA%3D%5Cfrac%7B226.446972%7D%7B0.009788%7D%5C%5C%20%5C%5CA%3D%5C%2423%2C134.61)
A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)
The amount of sample that will remain after 4000 years is; 4.8357 mg
The number of years that it will take for only 17 mg of the sample to remain is; 1076 years
<h3>How to solve exponential decay function?</h3>
A) Using the model for radioactive decay;
m(t)= m₀e^(-rt)
where;
m₀ is initial mass
r is rate of growth
t is time
Thus, we are given;
m₀ = 27 mg
r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043
and so we have;
m(t) = 27e^(-0.00043t)
c) The amount that will remain after 4000 years is;
m(4000) = 27e^(-0.00043 * 4000)
m(4000) = 27 * 0.1791
m(4000) = 4.8357 mg
d) For 17 mg to remain;
17 = 27e^(-0.00043 * t)
17/27 = e^(-0.00043 * t)
In(17/27) = -0.00043 * t
-0.4626/-0.00043 = t
t = 1076 years
Read more about Exponential decay function at; brainly.com/question/27822382
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Divide the amount she drove by the total amount she needs to drive, them multiply that answer by 100 to make it a percent. This will give you the percentage she drove. To find the percentage she has left,, subtract from 100%.
64 / 160 = 0.4
0.4 * 100 = 40% ( percent she has already driven)
100% - 40% = 60% left.
;
or p = -6