Answer:
Given f(x) = x2 + 3x – 1, find
a) f(1)
b) f(–1)
c) f(a)
d) f(x – 1)
Step-by-step explanation:
a) f(1) = (1)2 + 3(1) – 1 = 3
b) f(–1) = (–1)2 + 3(–1) – 1 = –3
c) f(a) = a2 + 3a – 1
d) f(x – 1) = (x – 1)2 + 3(x – 1) – 1
= x2 – 2x + 1 + 3x – 3 – 1 = x2 + x –3
X/2+1=y subtract 1 from both sides
x/2=y-1 multiply both sides by 2
x=2y-2
Answer:
a=8 b=3/2
Step-by-step explanation:
so here a is the initial value which 8
then we can plug in 2 for x and 18 for f(x) to find b
f(x)=8*b^x
18=8*b^2
18/8=b^2
9/4=b^2
b^2=(3/2)^2
b=3/2
