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Gala2k [10]
3 years ago
9

Pweasee help!!!!!!!!!!!!!​

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

B. \dfrac{1}{3}x-\dfrac{1}{4}y-\dfrac{4}{5}+\dfrac{1}{3}x-\dfrac{1}{4}y

Step-by-step explanation:

Consider all options:

A. In the expression

\dfrac{1}{3}x-\dfrac{1}{4}y-\dfrac{4}{5}+\dfrac{1}{3}x+\dfrac{1}{4}y

combine the like terms:

\left(\dfrac{1}{3}x+\dfrac{1}{3}x\right)+\left(-\dfrac{1}{4}y+\dfrac{1}{4}y\right)-\dfrac{4}{5}

Use distributive property:

x\left(\dfrac{1}{3}+\dfrac{1}{3}\right)+y\left(-\dfrac{1}{4}+\dfrac{1}{4}\right)-\dfrac{4}{5}=\dfrac{2}{3}x-\dfrac{4}{5}

This option is false.

2. In the expression

\dfrac{1}{3}x-\dfrac{1}{4}y-\dfrac{4}{5}+\dfrac{1}{3}x-\dfrac{1}{4}y

combine the like terms:

\left(\dfrac{1}{3}x+\dfrac{1}{3}x\right)+\left(-\dfrac{1}{4}y-\dfrac{1}{4}y\right)-\dfrac{4}{5}

Use distributive property:

x\left(\dfrac{1}{3}+\dfrac{1}{3}\right)+y\left(-\dfrac{1}{4}-\dfrac{1}{4}\right)-\dfrac{4}{5}=\dfrac{2}{3}x-\dfrac{1}{2}y-\dfrac{4}{5}

This option is true.

3. In the expression

\dfrac{1}{3}x-\dfrac{1}{4}y-\dfrac{1}{5}-\dfrac{1}{3}x-\dfrac{3}{5}-\dfrac{1}{4}y

combine the like terms:

\left(\dfrac{1}{3}x-\dfrac{1}{3}x\right)+\left(-\dfrac{1}{4}y-\dfrac{1}{4}y\right)+\left(-\dfrac{1}{5}-\dfrac{3}{5}\right)

Use distributive property:

x\left(\dfrac{1}{3}-\dfrac{1}{3}\right)+y\left(-\dfrac{1}{4}-\dfrac{1}{4}\right)-\dfrac{4}{5}=-\dfrac{1}{2}y-\dfrac{4}{5}

This option is false.

4. In the expression

\dfrac{1}{3}x-\dfrac{1}{4}y+\dfrac{2}{5}+\dfrac{1}{3}x-\dfrac{2}{5}-\dfrac{1}{4}y

combine the like terms:

\left(\dfrac{1}{3}x+\dfrac{1}{3}x\right)+\left(-\dfrac{1}{4}y-\dfrac{1}{4}y\right)+\left(\dfrac{2}{5}-\dfrac{2}{5}\right)

Use distributive property:

x\left(\dfrac{1}{3}+\dfrac{1}{3}\right)+y\left(-\dfrac{1}{4}-\dfrac{1}{4}\right)=\dfrac{2}{3}x-\dfrac{1}{2}y

This option is false.

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<h3>hello!</h3>

=====================================================

Parallel lines have the same slope.

So if the given line has a slope of 3, then the line parallel to it has the same slope (3)

Now, let's write the equation of the line in Point-Slope Form.

Remember, point-slope form looks like so:-

\bigstar{\underline{\boxed{\pmb{y-y1=m(x-x1)}}}

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and we're done!

=========================================================

<h3>note:-</h3>

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

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