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3 years ago

Solve for x: 3x-10 = 2(x+6)

Mathematics

1 answer:

77julia77 [94]3 years ago

7 0

Answer:

x = 22

Step-by-step explanation:

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4 years ago

Boris made $306 for 18 hours of work. At the same rate, how many hours would he have to work to make $119?

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4 years ago

A model rocket is launched directly upward at a speed of 50 meters per second from a height of 8 meters. The function f(t)=−4.9t

Gnoma [55]

Answer:

$t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36$

$t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158$

And since the time can't be negative we have that:

$t= 10.36 seconds$

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

Step-by-step explanation:

For this case we have the function of the height in terms of the time givenby:

$h(t) = -4.9t^2 +50 t+8$

And we want to known when the rockect hit the ground and for this case we need to solve the equation $h=0$

$-4.9t^2 +50 t+8 =0$

And as we can see we have a quadratic equation like this one:

$ax^2 +bx+c$

Where: $a =-4.9 , b =50 c =8$

And the general solutions are given by:

$x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

If we replace the values that we have we got:

$t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36$

$t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158$

And since the time can't be negative we have that:

$t= 10.36 seconds$

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

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4 years ago

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Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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3 years ago

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