50 dollars at max and Yelp
Explanation:
you may not qualify to enter that unit
How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
Learn more about Density of the Neutron star here:brainly.com/question/15700804
The answer to your question is eligibility for the national merit scholarship program
Answer:
10 in³
Explanation:
given:
square box = 4 in², length = 16 in
bar diameter = 2 in, length = 16 in
box volume (in solid) = 4 in² * 16 in = 64 in³
bar volume = pi * d² / 4 = 3.14 * 2² / 4 * 16 in = 50.24 in³
Volume of slotted box = 64 - 50 = 10 in³
