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Len [333]
2 years ago
8

Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 1

2 f(x) = 12x2 3x 3 f(x) = 3x – 12.
Mathematics
1 answer:
eimsori [14]2 years ago
8 0

The correct option is b.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

<h2>Leading coefficient </h2>

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.)  f(x) = -12x^2+3x+1 \\

b.)  f(x) = 3x^2+11x-12 \\

c.)  f(x) = 12x^2+3x+3\\

d.)  f(x) = 3x -12.

<h3 /><h3>Solution</h3>

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

Learn more about Quadratic Equation:

brainly.com/question/2263981

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<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

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