Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 1

Question

2 years ago

8

2 f(x) = 12x2 3x 3 f(x) = 3x – 12.

1 answer:

eimsori [14] · Answer 1 · 2023-01-05T08:16:10+03:00

The correct option is b.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

<h2>Leading coefficient </h2>

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.) $f(x) = -12x^2+3x+1 \\$

b.) $f(x) = 3x^2+11x-12 \\$

c.) $f(x) = 12x^2+3x+3\\$

d.) $f(x) = 3x -12.$

<h3 /><h3>Solution</h3>

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

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