Answer:
The answer to the question is
The ratio of the two gas pressures 
, that is Px to Py = 1/6
Step-by-step explanation:
Let the gases Volumes be V₁ and V₂
Where volume of X = V₁ and
volume of Y = V₂
The volume of Y is half the volume of X
∴ V₂ = 
× V₁
Let the number of moles be n₁ and n₂ in X and Y respectively
therefore n₂ = 3 × n₁
The pressure of the gas in X is Pₓ and the pressure of the gas in Y is 
then we have
P₁ × V₁ = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂
(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)
but T₁ = T₂
Therefore
(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂. However n₂ = 3 × n₁ and V₂ = × V₁ therefore substituting in the equation we have
(P₁ × V₁)/n₁ = (P₂ × × V₁ )/(3 × n₁) from where
P₁ /P₂ = ( × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6
The ratio of = 1/6
2 is the smallest prime factor of 12. 12 can evenly be divided by 2 so that makes 2 the smallest prime factor of 12.
These are the ten ways to
divide 96 into equal groups:
96 divided by 2 = 2 groups
of 48
96 divided by 48 = 48
groups of 2
96 divided by 12 = 12
groups of 8
96 divided by 8 = 8 groups
of 12
96 divided by 32 = 32
groups of 3
96 divided by 3 = 3 groups
of 32
96 divided by 24 = 24
groups of 4
96 divided by 4 = 4 groups
of 24
96 divided by 6 = 6 groups
of 16
<span>96 divided by 16 = 16
groups of 6</span>
The answer is in the photo provided
