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vredina [299]
3 years ago
15

HELP ME PLLEEAASSEEE

Mathematics
1 answer:
matrenka [14]3 years ago
6 0

Answer:

The relationship is that it might goes by 2

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The coefficient of the second term in the expansion of the binomial (4x+3y) to the 3rd power
kaheart [24]
You can solve this easily by using Pascal's Triangle (look that up if need be).

Here are the first four rows of P. Triangle:

                 1
           1           1
     1          2          1
1        3            3       1
 
 example:  expand (a+b)^3.
 
 Look at the 4th row.  Borrow and use those coefficients:
 
 1a^3 + 3 a^2b + 3ab^2  + b^3

Now expand (4x+3y)^3:

1(4x)^3 + 3(4x)^2(3y)  + 3(4x)*(3y)^2 + (3y)^3

Look at the 2nd term (above):

              3(4x)^2(3y)   can be re-written as 144x^2y.
 
The coeff of the 2nd term is 144.  Note that (4)^2 = 16    
3 0
3 years ago
Acellus
DENIUS [597]

Answer:

angle 7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help finding the slope
bulgar [2K]

Answer:

-1/3

Step-by-step explanation:

slope= \frac{4-1}{-4-5} =\frac{3}{-9} =\frac{1}{-3}

3 0
3 years ago
If y varies inversely with the square of x, and y=6 when x=4, find y when x=0.1
sergejj [24]

Answer:

9600

Step-by-step explanation:

y varies inversely with the square of x

y=k/(x^2)

for some non-zero constant k

y=6 when x=4

6=k/(4^2)

k=96

y=96/(x^2)

x=0.1

y=96/(0.1^2)

y=9600

8 0
3 years ago
What is the rule for the following geometric sequence? 64,128,256,512...
professor190 [17]

Answer:

B

Step-by-step explanation:

The explicit rule for a geometric sequence is

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 64 and r = \frac{a_{2} }{a_{1} } = \frac{128}{64} = 2 , then

a_{n} = 64 (2)^{n-1} → B

8 0
3 years ago
Read 2 more answers
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