Given:
Joining fee = $28
Fee of each event = $4
To find:
Total cost for someone to attend 4 events.
Solution:
Let the number of events be x and total fee be y.
Fee for 1 event = $4
Fee for x events = $4x
Joining fee remains constant. So, the total fee is
Substitute x=4 in this equation.
Therefore, total cost of 4 events is $44.
Answer:
10x+4b+3
Step-by-step explanation:
x+x+x+x+x+x+x+x+x+x+b+b+b+b+3
There are 10 x
4 b
and one number
10x+4b+3
41) you have a 40 day period
two visits with +75 centimeter growth each
3 visits with +6 each
in total 2*75+3*6=150+18=168
divide this by 40 days to get the average: 168/40=4.2 centimeters per day or 1.65 inches/day
42)
7x total
3x20
2x15
1x13
1x16
if you order these into a list:
13,15,15,16,20,20,20
the median is the middle value, in this case 16$
the mode is the most common value: 20$ which exists 3 times
Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.
Step-by-step explanation:
Given: ΔXYZ and ΔEFG such that ∠X=∠F
To prove they are congruent by using ASA or AAS conruency criteria
we need only one angle and side.
1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)
so we can apply ASA such that ΔXYZ ≅ ΔFEG.
2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.
5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that
ΔXYZ ≅ ΔFEG.
