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givi [52]
2 years ago
5

B) The perimeter of a squared field is 60 m. Find its area.​

Mathematics
1 answer:
Pani-rosa [81]2 years ago
6 0

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

Perimeter of square is :

\qquad \sf  \dashrightarrow \:4 \times side \: length

so, we can take side length as a, and solve for a ~

\qquad \sf  \dashrightarrow \:4a = 60

\qquad \sf  \dashrightarrow \:a = 60 \div 4

\qquad \sf  \dashrightarrow \:a = 15

Now, since we know the side length. let's find Area of square :

\qquad \sf  \dashrightarrow \: {15}^{2}

\qquad \sf  \dashrightarrow \:area = 225 \: m {}^{2}

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Answer: (-8/5,0)

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slavikrds [6]

We have a right triangle with a 15m hypotenuse and a 8m leg. If we use x for the missing leg then the Pythagorean Theorem states that:

15^2=8^2+x^2

Then we have to solve that equation for x:

\begin{gathered} x^2=15^2-8^2=225-64 \\ x^2=161 \\ x=\sqrt[]{161} \end{gathered}

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Answer:

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All these terms are matching with option 1. So, option 1 is the correct option

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What is the area of a triangle with a =2, b =7, and c =8?
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