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astraxan [27]
3 years ago
15

Indicate If these triangles are SSS SAS SAA ASA HL or none

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
8 0
The answer is SAS
Hope this helps......
Fed [463]3 years ago
5 0

Hypotnuse leg i belive my friend

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What is the median of the data set given below? 26, 39, 18, 21, 24, 48, 21, 35
sergiy2304 [10]
To find the Median, place the numbers you are given in value order and find the middle number. <span>If there are two middle numbers, you average them.
</span><span>18,  21,  21, 24,  26, 35, 39, 48

The two middle number are 24 and 26
Average 24 + 26/2 = 25
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3 years ago
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The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 mil
devlian [24]

Answer:

69.14% probability that the diameter of a selected bearing is greater than 84 millimeters

Step-by-step explanation:

According to the Question,

Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.

  • In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ

we have μ=87 , σ=6 & X=84

  • Find the probability that the diameter of a selected bearing is greater than 84 millimeters

This is 1 subtracted by the p-value of Z when X = 84.

So, Z = (84-87)/6

Z = -3/6

Z = -0.5 has a p-value of 0.30854.

⇒1 - 0.30854 = 0.69146

  • 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.

Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)

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3 years ago
What do we do to both sides of this equation to solve?
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<em>SIMPLY PLUGIN 4.8 FOR "A" EQUATION SHOULD LOOK LIKE V=4.8³ AND YOU WILL GET THE SAME ANSWER I DID</em>

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