Circle area equation is 3.14 x r squared.
So for question 1,
The radius is 3 cm.
We can square the radius ( 3 squared = 9).
After that, 9 x 3.14 = 28.26.
And after that we match our answers on the right hand column. Since we don't have the answer as given, we try to look for similar numbers. If we look at H, it shows us 0.2826 km squared. When cm is turned into km, the decimal moves two digits to its left. So for question 1, H is correct.
No because the more negative the temperature is , the more colder it gets
2x + 5 = 27
2x + 5 (-5) = 27 (-5)
2x = 22
2x/2 = 22/2
x = 11
hope this helps
The third one I think I’m sorry if I get this wrong
Answer:
![\left[\begin{array}{ccc}9\\10\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%5C%5C10%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Multiply the components of A by 3 then add corresponding components of
3a + b
3![\left[\begin{array}{ccc}2\\4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}3\\-2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}6\\12\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C12%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+
= ![\left[\begin{array}{ccc}6+3\\12-2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%2B3%5C%5C12-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
