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AleksandrR [38]
3 years ago
9

Solve for x. 2x + 5 = 27 What is the answer? 8.5 11 16 64

Mathematics
2 answers:
pishuonlain [190]3 years ago
5 0
2x + 5 = 27
2x + 5 (-5) = 27 (-5)
2x = 22

2x/2 = 22/2

x = 11

hope this helps
marta [7]3 years ago
5 0
The answer to your question is x=11

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Whats the radical form of 4/-40
faltersainse [42]

Answer:

Step-by-step explanation:1

7 0
3 years ago
Read 2 more answers
In a board game, players lose 50 points every time they land on a red space. If there is no other way to lose points and Jamie h
Simora [160]
Since players are losing points every time they land on a red space, it is -50,
Here's our equation where c equals the amount of times.
-50C=-450
We need C by itself, we need to divide.
-450÷-50=9
Since there is no other way to lose points, we don't have to worry about the slope in this equation. But, there might be a way to gain points. We have it set at 0 assuming that Jamie did not score any points. This allows us to get the minimum times her could have landed.
The minimum number of times he could have landed on a red space is 9 times.
7 0
3 years ago
Help please.
maria [59]
A1=-15
a2=a1+d→-4=-15+d→d=11
8 0
3 years ago
Brad has eight more nickels than quarters. Altogether he has $6.10. how many of each does he have
wlad13 [49]

Brad have 19 quarters and 27 nickels.

Step-by-step explanation:

Given,

Total worth of nickels and quarters = $6.10 = 6.10*100 = 610 cents

One quarter = 25 cents

One nickel = 5 cents

Let,

x represent the number of quarters.

y represent the number of nickels.

According to given statement;

25x+5y=610     Eqn 1

y = x+8              Eqn 2

Putting value of y from Eqn 1 in Eqn 2

25x+5(x+8)=610\\25x+5x+40=610\\30x=610-40\\30x=570

Dividing both sides by 30

\frac{30x}{30}=\frac{570}{30}\\x=19

Putting x=19 in Eqn 2

y=19+8\\y=27

Brad have 19 quarters and 27 nickels.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/9369548
  • brainly.com/question/9328925

#LearnwithBrainly

7 0
3 years ago
The seventh term of an arithmetic progression is equal to twice the fifth term. The sum
mario62 [17]

Answer:

a₁ = - 24

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₇ = 2a₅ , then

a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )

- a₁ - 2d = 0 → (1)

The sum to n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Given S_{7} = 84 , then

\frac{7}{2} (2a₁ + 6d) = 84

3.5(2a₁ + 6d) = 84 ( divide both sides by 3.5 )

2a₁ + 6d = 24 → (2)

Thus we have 2 equations

- a₁ - 2d = 0 → (1)

2a₁ + 6d = 24 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate d

- 3a₁ - 6d = 0 → (3)

Add (2) and (3) term by term to eliminate d

- a₁ = 24 ( multiply both sides by - 1 )

a₁ = - 24

6 0
3 years ago
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