Answer:
10 800 ml
Step-by-step explanation:
I hope this helps :}
Answer:
x=-3, x=1, x=8
Step-by-step explanation:
When you have to find the zero of an equation like (x+3) all you have to do is solve for x.
x+3=0 equal the equation to zero
x+3-3=0-3 cancel out 3
x=-3 answer
If you have to find the zero of an equation like f(x)=-2x^2 - 5x + 7 then you would have to factor the equation.
7*-2=-14 multiply
-7 & 2 find the two numbers that when multiplied =14 and when added = -5
(2x^2 + 2) (-7x + 7) replace -5 with -7 & 2
-2x (x - 1) -7 (x - 1) factor
(x - 1) (-2x - 7) rewrite
1st: x - 1 = 0
x = 1 : Answer
2nd: -2x - 7= 0
-2x - 7 + 7 = 0 + 7
-2x = 7
-2x / -2 = 7 / -2
x = 7 / -2 : Answer
Answer:
A. -4
Step-by-step explanation:
F(-1) means we must plug the number "-1" in for each x.
F(x) = x^2 + 3x - 2
F(-1) = (-1)^2 + 3(-1) - 2
= 1 - 3 - 2
= -4
Answer:
f(x) = 1 + x + (x²/2!) + (x³/3!) + ....... = Σ (xⁿ/n!) (Summation from n = 0 to n = ∞)
Step-by-step explanation:
f(x) = eˣ
Expand using first Taylor Polynomial based around b = 0
The Taylor's expansion based around any point b, is given by the infinite series
f(x) = f(b) + xf'(b) + (x²/2!)f"(b) + (x³/3!)f'''(b) + ....= Σ (xⁿfⁿ(b)/n!) (Summation from n = 0 to n = ∞)
Note: f'(x) = (df/dx)
So, expanding f(x) = eˣ based at b=0
f'(x) = eˣ
f"(x) = eˣ
fⁿ(x) = eˣ
And e⁰ = 1
f(x) = 1 + x + (x²/2!) + (x³/3!) + ....... = Σ (xⁿ/n!) (Summation from n = 0 to n = ∞)
