Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s 2 , what is the radius of the circle?
0.60 m 1.2 m 0.36 m 0.84 m

Answer 1

The image is answer.................

Answer 2

Answer:

Radius of the circle, r = 0.60 meters.

Step-by-step explanation:

It is given that,

Speed of the squirrel, v = 0.51 m/s

The centripetal acceleration of the squirrel, $a=0.43\ m/s^2$

We need to find the radius of the circle. The centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

$r=\dfrac{v^2}{a}$

$r=\dfrac{(0.51)^2}{0.43}$

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.