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Jet001 [13]
3 years ago
8

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.4

3 m/s 2 , what is the radius of the circle?
0.60 m 1.2 m 0.36 m 0.84 m

Mathematics
2 answers:
exis [7]3 years ago
4 0
The image is answer.................

Alik [6]3 years ago
3 0

Answer:

Radius of the circle, r = 0.60 meters.

Step-by-step explanation:

It is given that,

Speed of the squirrel, v = 0.51 m/s

The centripetal acceleration of the squirrel, a=0.43\ m/s^2

We need to find the radius of the circle. The centripetal acceleration is given by :

a=\dfrac{v^2}{r}

r=\dfrac{v^2}{a}

r=\dfrac{(0.51)^2}{0.43}

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.

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pochemuha
In order to compute the markup, compute the percentage like this:
38.50\times0. 32=12,32
The markup is then $12,32.
The selling price is the sum of the cost and the markup:
38.50+12,32=50,82
3 0
4 years ago
What is the justification for each step in solving the inequality? 3x+1/2<−x+4 Select from the drop-down menus to correctly j
patriot [66]

Answer:

see below

Step-by-step explanation:

(3x+1)/2<−x+4

Multiply each side by 2 using the multiplication property of equality

3x+1 < -2x +8

Subtract 1 from each side using the subtraction property of equality

3x < -2x+7

Add 2x to each side using the addition property of equality

5x < 7

Divide each side by 5 using the division property of equality

x < 7/5

3 0
3 years ago
Read 2 more answers
Which expression has a value equal to the value of the expression 4×(12+4) - (12÷3)
Rasek [7]
The answer to the problem is 28.
5 0
3 years ago
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The system of equations is given:
Nutka1998 [239]

Answer:

x=-1/85; y=-283/85; z=2/17

Step-by-step explanation:

Using an algebraic method like elimination or substitution would take a lot of steps which could lead to mistake the calculations. In this case, I decided to use the Gaussian elimination. We can express the system in matrix form as follows:

\left[\begin{array}{ccc}2&-4&6\\9&-3&1\\5&0&9\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}14\\10\\1\end{array}\right]

To begin the calculations, we write the system in augmented matrix form and use the Gaussian elimination:

\left[\begin{array}{ccccc}2&-4&6&|&14\\9&-3&1&|&10\\5&0&9&|&1\end{array}\right]

By applying the Gaussian elimination, the final matrix is the following:

\left[\begin{array}{ccccc}1&0&0&|&-1/85\\0&1&0&|&-283/85\\0&0&1&|&2/17\end{array}\right]

In order to verify the results, it´s enough to substitute the calculated values in the original equations to see if the equalities are correct. Here you can see the verification for all of the equations:

2(-1/85)-4(-283/85)+6(2/17)=14\\9(-1/85)-3(-283/85)+1(2/17)=10\\5(-1/85)+9(2/17)=1

6 0
3 years ago
I need help with this asap.
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Answer:

what do you need help with?

Step-by-step explanation:

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