Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
redth unless otherwise noted. n=1139; p=0.96
1 answer:
Answer:
μ−2σ = 1,089.26
μ+2σ = 1,097.62
Step-by-step explanation:
The standard deviation of a sample of size 'n' and proportion 'p' is:

If n=1139 and p =0.96, the standard deviation is:

The minimum and maximum usual values are:


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