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qaws [65]
1 year ago
12

It costs $6.45 to buy 5 songs on I-tunes. How much does it cost to buy 20 songs?

Mathematics
1 answer:
babunello [35]1 year ago
5 0

Answer:$25.80

Step-by-step explanation:

6.45/5 = 1.29

1.29 x 20 =25.80

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.
juin [17]

Answer:

B. {2,6,8}

Step-by-step explanation:

Since the range is your output, also known as your Y's, whenever you list them, they MUST be listed in order.

4 0
3 years ago
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3. What are the intersection points of the line whose equation is y=3x +3 and the
densk [106]

Answer:

Points of intersection of these graphs are (-2, -3) and (0.6, 4.8).

Step-by-step explanation:

Equation of the circle → (x - 2)² + y² = 25 ---------(1)

                                   → (x - 2)² + (y - 0)² = 5²

By comparing this equation with the standard equation of the circle,

(x - a)² + (y - b)²= r²

Here (a, b) is the center and r is the radius of the circle.

Therefore, center of the circle is (2, 0) and radius = 5 units

Second equation is a linear equation → y = 3x + 3 -------(2)

x-intercept of the equation → x = -1

y-intercept of the equation → y = 3

By graphing these equations we can get the point of intersections.

Solving these equations algebraically,

Substitute the value of y from equation (2) in the equation (1),

(x - 2)² + (3x + 3)² = 25

x² - 4x + 4 + 9x² + 18x + 9 = 25

10x² + 14x - 12 = 0

5x² + 7x - 6 = 0

x = \frac{-7\pm \sqrt{7^2-4(5)(-6)}}{2(5)}

x = \frac{-7\pm \sqrt{169}}{10}

x = \frac{-7\pm13}{10}

x = -2, 0.6

From equation (2),

y = -3, 4.8

Therefore, points of intersection of these graphs are (-2, -3) and (0.6, 4.8).

6 0
3 years ago
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Mashutka [201]

Answer:

{ \tt{ \blue{  - {3x}^{2} + 4x + 4 }}}

Step-by-step explanation:

{ \tt{3x -  {2x}^{2}  + 4 -  {x}^{2} + x }} \\

» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

= { \tt{( - 2 - 1) {x}^{2} + (3 + 1)x + 4 }} \\  = { \boxed{ \tt{ \:  -  {3x}^{2}  + 4x + 4}}}

7 0
2 years ago
The coefficient of determination is used to: compute correlations for truncated ranges. compare the relative strength of coeffic
kozerog [31]

Answer: compare the relative strength of coefficients.

Step-by-step explanation: The Coefficient of determination usually denoted as R^2 is obtained by taking the squared value of the correlation Coefficient (R). It's value ranges from 0 to 1 and the value obtained gives the proportion of variation in the dependent variable which could be attributed to it's correlation or relationship to th independent variable. With a R^2 value close to 1, this means a large portion of Variation in a variable A could be explained due to changes in variable B while a low value signifies a low variance between the variables. Hence, the Coefficient of determination is used in comparing the relative strength of the Coefficients in other to establish whether a weak or strong relationship exist.

6 0
2 years ago
Find the measure of &lt; 1. <br> m &lt; 1 = degrees
Furkat [3]
<1 = 120/2 = 60

answer
60 <span>degrees</span>
8 0
3 years ago
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