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kari74 [83]
3 years ago
10

Sasha performs an experiment. She chooses one marble from each of three sacks. The first sack has black (B) and white (W) marble

s. The
second sack has green (G) and yellow () marbles. The third sack has silver (S) and red (R) marbles.
Which tree diagram shows all the possible outcomes for this experiment?
Ос.
OB
OD

Mathematics
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

Option D is correct

Step-by-step explanation:

From the question, we have:

Sack\ 1: B, W

Sack\ 2: G, Y

Sack\ 3: S, R

Required

The tree diagram

The selection process is as follows:

Sack\ 1: B, W

Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y) -- i.e. we write sack 2 as a subset of 1

Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R)) -- i.e. we write sack 3 as a subset of 2

<em>The only tree diagram that illustrates this is: option D</em>

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Solve the following equation:<br> 9n² - n - 2/3 = 0
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Answer:

see explanation

Step-by-step explanation:

Given

9n² - n - \frac{2}{3} = 0 ← multiply through by 3 to clear the fraction

27n² - 3n - 2 = 0 ← factoring

Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term

product = 27 × - 2 = - 54 and sum = - 3

The factors are - 9 and + 6

Use these factors to split the n- term

27n² - 9n + 6n - 2 = 0 ( factor the first/second and third/fourth terms )

9n(3n - 1) + 2(3n - 1) = 0 ← factor out (3n - 1) from each term

(3n - 1)(9n + 2) = 0

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This is known as Einstein's proof, not because he was the first to come up with it, but because he came up with it as a 15 year old boy.

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