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ser-zykov [4K]
2 years ago
13

What are partial quotients

Mathematics
1 answer:
Degger [83]2 years ago
3 0

A partial quotient refers to a method for solving large division problems in mathematics. An alternative to the traditional long division method is the partial quotient method. This partial quotient division method is used to make multi-digit division simple and easy to understand and perform.

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Simplify -2 1/9 - (-4 1/9)
ZanzabumX [31]

Answer:

2

Step-by-step explanation:

The easiest thing is to convert it to an improper fraction.

-2 1/9 turns into -19/9. -4 1/9 turns into -37/9.

-19/9 - (-37/9) here you would add because you are subtracting a negative number.

-19/9 + 37/9 change it to positive and then add.

-19+37=18

it was 18/9. that simplified is 2.

4 0
3 years ago
Pepper Jackie Has 7.5 bags of mulch to cover 12yds2 is edible flowers beds. If she wants to distribute the mulch evenly over the
AleksandrR [38]
Divide 7.5 by 12 which equals 0.625
The answer should be less than 1 bag.
6 0
3 years ago
Read 2 more answers
Brainliest pls help
Airida [17]
<h3>Volume:</h3>

With this prism, first separate it into a rectangular prism and a right triangle prism.

First, with the rectangular prism, it would have the units 5 * 5 * 6.3. Then with the right triangle prism, it would take the rest of the remaining space of it, being 3 * 5 * 6.3

The equation for the volume of a rectangular prism is L*W*H and the equation for the volume of a right triangle prism is (L*W*H) / 2.

With this, plug the numbers in for both prisms to get the volume of each of them:

<u>Rectangular prism Volume</u>

5*5*6.3

<em>157.5</em>

<u>Right triangle prism Volume</u>

(3*5*6.3) / 2

94.5 / 2

<em>47.25</em>

Lastly, combine these two values to get the total volume:

157.5 + 47.25 = 204.75 (Round Up) -->

<em><u>204.8 cm^3 = Total Volume </u></em>

<h3>Surface Area:</h3>

Next, with the surface area of the prism. For this, lets combine all of the faces of the prism then add them all up.

First, lets do the bottom of the prism, or the base. It uses the lengths 8 cm and 6.3 cm. Lets do L * W to get the area of this face:

8 * 6.3 = 50.4

Next, lets do the slant side of it, which has the lengths 5.8 and 6.3.

5.8 * 6.3 = 36.54

Then, the top side with the lengths 5cm and 6.3 cm.

5.3 * 6.3 = 33.39

After that, the left side face that opposite to the slantly one:

5 * 6.3 = 31.5

Saving the most tedious part of it for last, the right trapezoids. Luckily, there is an equation for this:

<em>1/2 x (Sum of parallel sides) x (perpendicular distance between the parallel sides).</em>

<em>So, within each of these right </em>trapezoids, there's the parallel sides of 5 and 8. There's also a perpendicular side of 5cm. With this, we can plug this into the equation to solve for this part:

1/2 x (5+8) * (5)

1/2 x (13) * (5)

1/2 x (65)

32.5

Since there's two of them, times this by 2:

32.5 * 2 ---> 65.

Now, with the area of all of the faces, these can be added up for the total surface area:

50.4 + 36.54 + 33.39 + 31.5 + 65 ---> 216.83 (Round Down)-->

<u><em>216.8 cm^2 = Total Surface Area</em></u>

<em />

8 0
3 years ago
A complete table with values for x or y that make this equation true:3x+y=15
Reika [66]

Answer:

Table is attached

Step-by-step explanation:

We are given equation as

3x+y=15

We will complete each column

First column:

we are given x=2 and we have to find y

3\times 2+y=15

6+y=15

y=9

Second column:

we are given y=3 and we have to find x

3x+3=15

3x=12

x=4

Third column:

we are given x=6 and we have to find y

3\times 6+y=15

18+y=12

y=-6

Fourth column:

we are given x=0 and we have to find y

3\times 0+y=15

0+y=15

y=15

Fifth column:

we are given x=3 and we have to find y

3\times 3+y=15

9+y=15

y=6

Sixth column:

we are given y=0 and we have to find x

3x+0=15

3x=15

x=5

Seventh column:

we are given y=8 and we have to find x

3x+8=15

3x=7

x=\frac{7}{3}

now, we can complete table



8 0
3 years ago
What does a reminder means in the context of the problem
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What ever solution is left over after solved 
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3 years ago
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