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algol [13]
3 years ago
6

Find e and d3e+d=8 2e+d=8​

Mathematics
2 answers:
Westkost [7]3 years ago
7 0

Answer:

Step-by-step explanation:

son4ous [18]3 years ago
5 0
3e+d=8
2e+d=8
Multiply the second equation by -1
You get
-3e-d=-8
Use eliminating methods
-3e-d=-8
2e+d=8
We get
-e=0
So e=0
Find e by substitute it in one of the equation
2*0+d=8
D
d=8
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What is -5g + ( -17fg ) =
Anika [276]

Hello from MrBillDoesMath!

Answer:

-g (5 + 17f)    



Discussion:

The terms only have the factor "g" in common so


-5g + ( -17fg) =                       => factor "g" from each term

g ( -5 - 17f) =

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is as much as it can be factored.


Thank you,

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4 years ago
If f(x) = 2x² + 5 and g(x) = x² - 2, find
IgorLugansk [536]

Answer:

C. x² + 7

Step-by-step explanation:

If f(x) = 2x² + 5 and g(x) = x² - 2, then

(f - g)(x) = f(x) - g(x)

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            = 2x² + 5 - x² + 2

            = 2x² - x² + 5  + 2

            = x² + 7

           

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after that what u wrote i couldn't understand

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