Answer:
13.86 ft/sec
Step-by-step explanation:
If we let x = distance batter has run at time t and D = distance from second base to the batter at time t, then we know
and we want
when he is halfway (at x = 45).
Using Pythagoras theorem

When x=45


Thus, when the batter is halfway to first base, the distance between second base and the batter is decreasing at the rate of about 13.86 ft/sec.
10% of 70 is 7
.1 times 70 is 7
so the answer should be 70
Answer:
2(-2)-5(-2)+12
-4-(-10)+12
6+12
18
Step-by-step explanation: