Answer:
<h2>d. $250</h2>
Step-by-step explanation:
We can use the equation of a straight line to model the cost of servicing the car.
let the cost be y and the number of hours be x
and the charge per hour is m
y=mx+c
y=50x+25
given that the time is 3.45 hours it is assumed that the charge is for 4 hours since for a fraction of 0.45 hours we are charged $50
y=50(4)+25
y=200+25
y=$225
Sorry if this is messy but I hope it helps you
Answer:
13
Step-by-step explanation:
(12*2)/2+1 > 24/2+1 > 12+1 > 13
To set up or model a linear equation to fit a real-world application, we must first determine the known quantities and define the unknown quantity as a variable. Then, we begin to interpret the words as mathematical expressions using mathematical symbols. Let us use the car rental example above. In this case, a known cost, such as $0.10/mi, is multiplied by an unknown quantity, the number of miles driven. Therefore, we can write
0.10
x
. This expression represents a variable cost because it changes according to the number of miles driven.
If a quantity is independent of a variable, we usually just add or subtract it according to the problem. As these amounts do not change, we call them fixed costs. Consider a car rental agency that charges $0.10/mi plus a daily fee of $50. We can use these quantities to model an equation that can be used to find the daily car rental cost
C
.
C
=
0.10
x
+
50
When dealing with real-world applications, there are certain expressions that we can translate directly into math. The table lists some common verbal expressions and their equivalent mathematical expressions.
