All categories

3 years ago

How many 1/8 servings can I get from 3/4

Mathematics

2 answers:

yanalaym [24]3 years ago

6 0

Answer:

Step-by-step explanation:

you convert 3/4 into 8ths which will be 6/8

Alona [7]3 years ago

5 0

Answer:

6 1/8th cups in 3/4 cups

Step-by-step explanation:

You might be interested in

Slow and steady wins the race. The leatherback sea turtle is the fastest known reptile, with a maximum speed of 21.9221.9221, po

topjm [15]

Complete question:

The leatherback sea turtle is the fastest known reptile, with a maximum speed of 21.92 miles per hour (mph).

Which of the following equations, where d is distance in miles and t is time in hours, represents a speed that is less than that of the leatherback sea turtle?

Select all that apply.

a. d = 2.192t

b. d = 20t

c. d = 22t

d. d = 30t

Answer:

a (2.192t) and b (20t)

Step-by-step explanation:

Since units for distance and time are all measured in miles and hours respectively, we can simply compare the values of the options given with the leatherback turtle speed and express if the value is lower or not. We must pay special attention to the decimal separator in some cases.

Leatherback sea turtle: d = 21.92t

a. d = 2.192t is less than 21.92t

b. d = 20t is less than 21.92t

c. d = 22t is more than 21.92t

d. d = 30t is more than 21.92t

7 0

2 years ago

Read 2 more answers

What is the slope of a line parallel to the graph of y+1=-8(x-2)?

inn [45]

Y+1=-8(x-2)
y+1=-8x+16
y=-8x+15
The slope would be -8

8 0

3 years ago

Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m

JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment .

A) Determine the test statistic

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5) / $\sqrt{0.5*0.5 / 200}$ = 2.12

b) determine the p-value

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 ) = 1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0

3 years ago

I need help with multiplying and dividing powers

Tamiku [17]

You need to know these two formulas:

$\huge a^b \times a^c = a^{b+c}\\\\\huge \frac{a^b}{a^c}=a^{b-c}$

For example,

$5^2 \times 5^3 = 5^{2+3} = 5^5$

$\frac{2^6}{2^4} = 2^{6-4} = 2^2$

6 0

3 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

1. A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin; 2. The radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball; 3. The volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

$\\ 1 \leq a < 10$ (3)

Then, b represents the order of magnitude of such a number (Order of magnitude (2020), in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The La Plata river dolphin weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the scientific notation):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin.

<h3>Second case</h3>

Following the same reasoning, we can conclude that the radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball:

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$