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pshichka [43]
3 years ago
12

A number line goes from 0 to 30. Closed circles are at 6 and 25. A line is drawn from point 6 to point 25. Ari is swimming a 25-

meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At what meter mark does Ari catch up to Amanda? Round to the nearest tenth, if necessary. Ari catches up to Amanda at meters.
Physics
2 answers:
a_sh-v [17]3 years ago
8 0

The position on the meter mark where Ari catches up with Amanda is 19.3 m.

The given parameters:

  • <em>Range of the number line, = 0 to 30</em>
  • <em>Position of the closed circles, = 6 and 25</em>
  • <em>The ratio between the initial position and final position of Ari = 7:3</em>

The distance between 6 m mark and 25 m mark is calculated as follows;

d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m

The distance traveled by Ari before catching up with Amanda is calculated as follows;

total ratio = 7 + 3 = 10

distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m

The position of Ari from the 6 m mark is calculated as follows;

position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m

Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.

Learn more about partition of line segments here: brainly.com/question/11764811

trapecia [35]3 years ago
4 0

Answer:

The above answer is correct! The answer is 19.3 meters :)

Explanation:

adding a ss for proof!

hope this helps :D

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Harlamova29_29 [7]

4.266 m is the radius of the circular path the electron follows.

Given

Speed of electron (v) = 7.5 × 10⁶ m/s

Earth's Magnetic Field (B) = 1 × 10⁻⁵ T

We already know that

Mass of electron (m) = 9.1 × 10⁻³¹ kg

Charge on electron (q) = 1.6 × 10⁻¹⁹ C

According to the formula

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Radius of circular path(r) = m × v/q × B

Put the values into the formula

r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵

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Learn more about magnetic field here brainly.com/question/26257705

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Answer:

0.958891203 m/s²

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\mu = Coefficient of friction = 0.25

Force of friction acting on the force applied

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Acceleration is given by

a=\frac{F_n}{m}\\\Rightarrow a=\dfrac{87.97167}{\dfrac{900}{9.81}}\\\Rightarrow a=0.958891203\ m/s^2

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g If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resi
Anettt [7]
<h2>Question:</h2>

In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?

Answer:

9.1Ω

Explanation:

The circuit diagram has been attached to this response.

(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

\frac{1}{R_X} = \frac{1}{R_1} + \frac{1}{R_2}

=> R_{X} = \frac{R_1 * R_2}{R_1 + R_2}             ------------(i)

From the question;

R1 = 3Ω,

R2 = 7Ω

Substitute these values into equation (i) as follows;

R_{X} = \frac{3 * 7}{3 + 7}

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(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.

Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e

R = Rₓ + R3

Rₓ = 2.1Ω

R3 = 7Ω

=> R = 2.1Ω + 7Ω = 9.1Ω

Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω

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Answer:

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Explanation:

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