Question

A 900 N crate is being pulled across a level floor by a force F of 340 N at an angle of 23° above the horizontal. The coefficient of kinetic friction between the crate and the floor is 0.25. Find the magnitude of the acceleration of the crate.

Answer 1

Answer:

0.958891203 m/s²

Explanation:

N = Weight of crate = 900 N

$\mu$ = Coefficient of friction = 0.25

Force of friction acting on the force applied

$f=\mu N\\\Rightarrow f=0.25\times 900\\\Rightarrow f=225\ N$

Force used to pull the crate

$F=340cos 23\\\Rightarrow F=312.97165\ N$

The net force is

$F_n=F-f\\\Rightarrow F_n=312.97167-225\\\Rightarrow F_n=87.97167\ N$

Acceleration is given by

$a=\frac{F_n}{m}\\\Rightarrow a=\dfrac{87.97167}{\dfrac{900}{9.81}}\\\Rightarrow a=0.958891203\ m/s^2$

The magnitude of the acceleration of the crate is 0.958891203 m/s²