The total thermal power generated by this plutonium source is determined as 5.65 J/s.
<h3>Total thermal power generated</h3>
The total thermal power generated by this plutonium source is determined as follows;
ΔP = Eλ
where;
- E is the energy of the particles = 5.6 mev
- λ is the activity of the plutonium, which should be = 6.3 x 10¹⁵ s⁻¹
ΔP = (5.6 mev) x (6.3 x 10¹⁵ s⁻¹)
ΔP = (5.6 x 10³ x 1.6 x 10⁻¹⁹ J) x (6.3 x 10¹⁵ s⁻¹)
ΔP = 5.65 J/s
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Stan looga
this is correct answer
100 cm is 1 meter. So your answer would be 0.362 meters.
V=25(7.5/(7.5+5)). This is the voltage divider equation
