The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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A=16.35
B=21.5. ................
In this problem, we have to find the factor which will
make (1 / 10) equal to (2 / 5). Therefore we can write it as:
x (1 / 10) = 2 / 5
where x is the number of people who ate the blueberries
x = (2 / 5) / (1 / 10)
x = 4
<span>Therefore 4 people ate the blueberries.</span>
Answer:
9 mm wide
Step-by-step explanation:
Perimeter = length x 2 + width x 2
34 mm = 16 mm + ?
34mm = 16 mm + 18 mm
18/2 = 9
9 mm wide
