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Schach [20]
3 years ago
14

The Ferris wheel makes 12 revolutions per ride how far would someone travel during one ride

Mathematics
1 answer:
professor190 [17]3 years ago
5 0
Question how much distance is in each revolvison

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Data from the Centers for Medicare and Medicaid Services indicates that the annual per capita out-of-pocket expenses for health
Talja [164]

Answer:

During the year 2021.

Step-by-step explanation:

As we have a function that defines the annual per capita out-of-pocket expenses for health care, we can work with it.

Knowing that, <u>we clear x</u> (<em>this is the number of years past the year 2000, so it will contain our desired information</em>).

y=39.6x+543\Leftrightarrow x=\frac{y-543}{39.6}

Now, as we want to know when are the per capita out-of-pocket expenses for health care predicted to be $1400, and <em>this total is our variable y</em>, then

x=\frac{1400-543}{39.6}\approx 21.6

Finally, we know that <u>x is the number of years past the year 2000</u>, so the answer is that during the year 2021, <em>the per capita out-of-pocket expenses for health care are predicted to be $1400</em>.

3 0
3 years ago
Solve this equation 4(2)-3= 2(2) + 9​
strojnjashka [21]

Answer:5=13

Step-by-step explanation:

Open parenthesis so you do 4 time 2 and 2 times 2. you get 8-3=4+9. 8-3=5 and 4+9=13. So your final answer is 5=14. I am not sure if you can simplify it further.

3 0
3 years ago
Please help me solve this probe
allsm [11]
Since it wants total to brown you have to do the ratio in that order.
There are a total of 8 puppies of which two are brown.
T:B
8:2 reduces to 4:1
4 0
3 years ago
How can you write 1 9/100 in a decimal
grigory [225]
1 9/100

= 1 + 9/100

= 1/1 + 9/100

= (1/1 * 100/100) + 9/100

= 100/100 + 9/100

= 109/100

= 109 ÷ 100

= 1.09

6 0
2 years ago
Read 2 more answers
System of equations x-y-2z=4, -x+2y+z=1, x+y-3z=11. Solve by elimination
Wittaler [7]
x-y-2z=4 \\ -x+2y+z=1 \\ x+y-3z=11 \\ \\  \left \{ {{x-y-2z=4 } \atop {-x+2y+z=1}} \right \ and \ \left \{ {{-x+2y+z=1 } \atop {x+y-3z=11}} \right \\ \\  \hbox{1st system:} \\ x-y-2z=4 \\ \underline{-x+2y+z=1} \\ x-x+2y-y-2z+z=4+1 \\ y-z=5

\hbox{2nd system:} \\ -x+2y+z=1 \\ \underline{x+y-3z=11} \\ x-x+2y+y-3z+z=1+11 \\ 3y-2z=12 \\ \\ \hbox{now compare both:} \\ y-z=5 \ \ \ |\cdot (-2) \\ 3y-2z=12 \\ \\ -2y+2z=-10 \\ \underline{3y-2z=12 \ \ \ \ \ \ } \\ 3y-2y+2z-2z=12-10 \\ y=2 \\ \\ 2-z=5 \\ -z=3 \\ z=-3 \\ \\ x-2-2 \cdot (-3) = 4 \\ x-2+6=4 \\ x+4=4 \\ x=0

The answer is: x=0, y=2, z=-3.
3 0
3 years ago
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