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lesya [120]
3 years ago
12

Expand brackets 4(y+2)

Mathematics
2 answers:
Margaret [11]3 years ago
8 0

Answer:

16(y+2)

Step-by-step explanation:

Tcecarenko [31]3 years ago
6 0
4(y+2)= 4y+2 i hope this helps!
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The population of a small town was 10,800 in 2002. Since then the population has decreased at a rate of 2.5% each year. Write an
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Answer:

See below

Step-by-step explanation:

A 2.5 % decrease means  97.5 % remains (.975)

population =  10800 ( .975) ^n     where n = years past 2002

  in 2020    n = 18

    10800 (.975)^18 = 6847  people

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2 years ago
What is the midpoint of point A and B? On a graph.
allochka39001 [22]

Answer:

Where i da graph.?>?>?>?>

Step-by-step explanation:

5 0
3 years ago
NEED HELP URGENTLY!!!
morpeh [17]

Answer:

2,9

Step-by-step explanation:

find difference between 16 and 9, and then subtract it by 9. find difference between3 and 6 then add that to 6.

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Chuge%5Csf%5Cunderline%7BQuestion%7D" id="TexFormula1" title="\huge\sf\underline{Question}"
vekshin1

{\qquad\quad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} }  = 34

[ add 2 on both sides ]

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} } + 2  = 34 + 2

[ form identity : a² + b² + 2ab ]

\qquad \sf  \dashrightarrow \:  {(x)}^{2}  +  { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2}  + 2 \sdot(x)  \sdot  \bigg(\cfrac{1}{x} \bigg)  = 36

[ a² + b² + 2ab = (a + b)² ]

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{2}  = 36

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{}  =  \sqrt{ 36}

\qquad \sf  \dashrightarrow \: x  +  \cfrac{1}{x}    =   \pm 6

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

8 0
2 years ago
I am thinking of a number. If I double
JulijaS [17]

Answer:

well if you double 1 then that equals 2 then you add five is 7 then double it is 14...so...yeah whatever I just said

6 0
3 years ago
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