Answer: Yes, since as we move from left to right in the x axis, the plots in the x axis along with the plots in the y axis also increases.
Step-by-step explanation:
-10t - (-17t) - 10t + (-13) = 11 (two negative signs makes a positive)
-10t + 17t - 10t - 13 = 11 Combine like terms
-3t - 13 = 11 Add 13 on both sides
-3t = 24 Divide -3 on both sides
t = -8
Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
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My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
The answer is D.
The first step is to use the distributive property and turn 5(x-4) into 5x - 20.
You then move the twenty into the right equation by adding 20 to both sides. The final step is to move the 3x into the left equation by subtraction and then dividing both sides by 2 to isolate x. Hope this helped !!
