Answer:
12.50x less than or equal to $200
Step-by-step explanation:
Answer:
1/4 hopefully this helps you with work
Answer:
D)
Step-by-step explanation:
ASSUMING NORMAL DISTRIBUTION, LESS THAN 10% AT LOWER END
OF 15.34 MEANS [DENOTING MEAN BY M AND Standard Deviation. BY S]
M±AS=20%....................M-AS=15.34
FOR 20% LEVEL .......A=1.281........FROM TABLES
M-1.281×S=15.34............................1
SIMILARLY
M±BS=40%...................M+BS=16.31
FOR 40% LEVEL .............B=0.841...................FROM TABLES
M+0.841×S=16.31.............................2
EQN.2 - EQN.1
2.122×S=0.97
S=0.457=0.46
M=15.926= 15.93
HENCE, D IS THE ANSWER
that is D. μ = 15.93, σ =.46
Answer:
0.4
Step-by-step explanation:
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence .
- The standard deviation is of 1 gram, hence .
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:
The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213