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lorasvet [3.4K]
2 years ago
5

In six years Xavier will be 3 times older than Joanne is today. Joanne is 24. How old is Xavier?

Mathematics
1 answer:
Elza [17]2 years ago
7 0

Answer:

72

Step-by-step explanation:

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А<br> D<br> 11x+8<br> 950<br> B<br> с<br> Find the value of X
Ivenika [448]

Answer:

write your question properly...

4 0
2 years ago
Which of the following is the correct factored form for the given equation? 2x^2+8x+6=0
3241004551 [841]
It would be 2(x+3)(x+1)=0

Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
6 0
3 years ago
Solve and find X. <br> Question says 5-x / 2 = 2x-7
poizon [28]

Answer:

x = 3.8

Step-by-step explanation:

The equation is (5 - x) / 2 = 2x - 7

Multiply both sides by 2:

5 - x = 4x - 14

Add 14 to both sides:

19 - x = 4x

Add x to both sides:

19 = 5x

Divide both sides by 5 to isolate x:

3.8 = x

Therefore, x = 3.8.

7 0
3 years ago
Read 2 more answers
The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


5 0
2 years ago
Read 2 more answers
An equation that is true when y=-0.5
KIM [24]
2y+1=0.5+y.

Hope this helps!
3 0
3 years ago
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