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vichka [17]
2 years ago
9

A bag contains 8 red marbles, 3 blue marbles, and 1 green marble. Find P(not blue). a. 9 c. One-fourth b. Four-thirds d. three-f

ourths
Mathematics
1 answer:
gayaneshka [121]2 years ago
7 0

In order to find the probability of drawing a marble that is NOT BLUE, we must find the ratio of non-blue marbles to the total amount of marbles

Let's count how many marbles total there are first

8 red + 3 blue + 1 green = 12 marbles total

Now, how many marbles are there that <u>ARE NOT BLUE </u>

8 red + 1 green = 9 marbles <u>THAT ARE NOT BLUE </u>

Now<em> let's create a ratio</em> to find a probility

9/12

This can be simplified to 3/4 by taking out the common factor of 3

Your answer is D! "three-fourths"

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Complete the missing value/help?
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What it is basically asking is if Y = -4, find the value of x in the equation 6x + 7y = 4x + 4y

To solve this you just need to plug in -4 for y and solve for x

6x + 7(-4) = 4x + 4(-4)

6x - 28 = 4x - 16

Now isolate x by adding 28 to both sides

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and subtract 4x from both sides

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divide both sides by 2

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x = 4

x = 4, y = -2

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Hope it helps :)

Bransliest would be appreciated

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