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3 years ago

14

Below is the graph of y=x^3. Translate it to make it the graph of y=(x-4)^3-1

2 answers:

Vadim26 [7]3 years ago

8 0

Answer:7=0.5 |x-4| -3

+3 +3

10=0.5 |x-4|

10/0.5=0.5/0.5 |x-4|

20=|x-4|

^

-20=x-4 20=x-4

+4 +4 +4 +4

-16=x 24=x

The answers are -16=x and 24=x

Hope this helps, an if it pleases you put as the brainliest answer

denis-greek [22]3 years ago

5 0

Answer:

-16=x and 24=x

Step-by-step explanation:

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The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

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Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

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The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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Step-by-step explanation:

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