Answer:
help with what? what is your q u e s t i o n
Step-by-step explanation:
Answer:
The pairs of integer having two real solution for
are




Step-by-step explanation:
Given

Now we will solve the equation by putting all the 6 pairs so we get the following
for 
for 
for 
for 
for 
for 
The above all are Quadratic equations inn general form 
where we have a,b and c constant values
So for a real Solution we must have

for
we have
which is less than 0 ∴ not a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is equal to 0 ∴ a real solution.
for
we have
which is less than 0 ∴ not a real solution.
Answer:
It should look like a v with the origin at +0.5
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
6+6+10+10+15+15
The all go over 18 so put them all over 18
16/18+12/18+3/18=31/18
31/18 or 1.722222222........