The formula of a distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have the points (-1, 8) and (5, -2). Substitute:
![d=\sqrt{(5-(-1))^2+(-2-8)^2}=\sqrt{6^2+(-10)^2}=\sqrt{36+100}=\sqrt{136}\\\\=\sqrt{4\cdot34}=\sqrt4\cdot\sqrt{34}=\boxed{2\sqrt{34}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285-%28-1%29%29%5E2%2B%28-2-8%29%5E2%7D%3D%5Csqrt%7B6%5E2%2B%28-10%29%5E2%7D%3D%5Csqrt%7B36%2B100%7D%3D%5Csqrt%7B136%7D%5C%5C%5C%5C%3D%5Csqrt%7B4%5Ccdot34%7D%3D%5Csqrt4%5Ccdot%5Csqrt%7B34%7D%3D%5Cboxed%7B2%5Csqrt%7B34%7D%7D)
2 3 I think sorry if im wrong
Answer: 2.7545
The question was a little off, but I can understand enough
Step-by-step explanation:
Grade Grade Point(x) Course Credit(y) Product(xy)
A 4 3 12
B 3 4 12
B 3 4 12
B 3 4 12
C 2 2 4
D 1 3 3
Total 20 55
This means, the GPA of the student is :
![GPA=\frac{55}{20}](https://tex.z-dn.net/?f=GPA%3D%5Cfrac%7B55%7D%7B20%7D)
![2.75](https://tex.z-dn.net/?f=2.75)
Answer:
766m (3 s.f.)
Step-by-step explanation:
Please see the attached picture for the full solution.
We know, percentage change = (final value-Initial value) / Initial value × 100
Here, Initial value = 4.2 Ft³
Final value = 5.6 Ft³
Substitute their values into the expression:
% change = (5.6 - 4.2)/4.2 × 100
% change = 1.4/4.2 × 100
% change = 33.33%
In short, Your Final answer would be 33.33%
Hope this helps!