Answer:
4
Step-by-step explanation:
gcf(432,320,228)=gcf(gcf(432,320),228)
432=320(1)+112
320=112(2)+96
112=96(1)+16
96=16(6)
So the gcf(432,320)=16.
So now we need to find gcf(16,228)
228=16(14)+4
16=4(4)
Therefore,
gcf(432,320, 228)
=gcf(gcf(432,320),228)
=gcf(16, 228)=4
===================================
432=4(108)=4(2)(54)
=4(2)(6)(9)=2(2)(2)(2)(3)(3)(3)
320=4(80)=4(2)(40)=2(2)(2)(4)(10)
=2(2)(2)(2)(2)(2)(5)
228=4(57)=2(3)(38)=2(2)(3)(19)
All three of them have 2*2 in commom, so the greatest common factor is 4.
Answer:
(5$ = 8) (10$=16) and im still not sure for w then part. b 24$
Step-by-step explanation:
5x1.6=8
10x1.6=16
i need help with w
15x1.6=24
sorry if this didnt help
I hope this helps you
1.k^2+5k-6=0
a=1
b=5
c= -6
disctirminant =b^2-4ac
disctirminant =5^2-4.1. (-6)
disctirminant =49
x1= -(5)+ square root of 49/2.1
x1=-5+7/2
x1=1
x2= -5- square root of 49/2.1
x2= -5-7/2
x2= -6
Let a ∈ A. Then a is some integer that is divisible by 4, so we can write a = 4k for some integer k.
We can simultaneously rewrite a as a = 2•2k, so 2 clearly divides a, which means a ∈ B as well.
Therefore A ⊆ B.
Answer:
2x³ - 3y + z²
Step-by-step explanation:
-2x³ – y – 2z² + 4x³ – 2y + 3z² Combine like terms
-2x³ + 4x³ – y – 2y – 2z² + 3z²
2x³ - 3y + z²
