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stira [4]
2 years ago
11

Can someone help me label this flower??

Physics
1 answer:
tensa zangetsu [6.8K]2 years ago
7 0

Hope this helps!!!!!!!!!!!!!

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Fluid of intelligent​
GarryVolchara [31]

"Fluid intelligence involves being able to think and reason abstractly and solve problems. This ability is considered independent of learning, experience, and education. Examples of the use of fluid intelligence include solving puzzles and coming up with problem-solving strategies."  

- Verywell Mind

8 0
2 years ago
A step-down transformer has more loops on which coil?
Nesterboy [21]
A step-down transformer has more loops in :  A. Primary coil

Primary coil refers to the coil to which alternating voltage is supplied. It's usually connected to the AC supply

hope this helps
6 0
3 years ago
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You could use newton’s second law to calculate the force applied to an object if you knew the objects mass and its _____.
olga2289 [7]

Answer:

You could use newton’s second law to calculate the force applied to an object if you knew the objects mass and its <u>acceleration.</u>

Explanation:

By, Newtons second law, the force applied on an object directly varies with the acceleration caused and the mass of the object.

This is given by :

F=m\ a

Where F represents force applied on the object , m represents mass of the object and a represents the acceleration.

In order to calculate force applied on object we require the mass of the object and its acceleration. The force can be calculated by finding the product of mass and acceleration of the object.

4 0
3 years ago
When a planet orbits the Sun, the
Anna [14]
I’m not sure I think it’s A
6 0
2 years ago
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An ice skater spins at 2.5 rev/s when his arms are extended. He draws his arms in and spins at 10.0 rev/s. By what factor does h
Rainbow [258]

Answer:

The moment of inertia decreased by a factor of 4

Explanation:

Given;

initial angular velocity of the ice skater, ω₁ = 2.5 rev/s

final angular velocity of the  ice skater, ω₂ = 10.0 rev/s

During this process we assume that angular momentum is conserved;

I₁ω₁ = I₂ω₂

Where;

I₁ is the initial moment of inertia

I₂ is the final moment of inertia

I_2 = \frac{I_1 \omega_1}{\omega_2} = \frac{I_1*2.5}{10} \\\\I_2 = 0.25I_1 = \frac{1}{4}I_1

Therefore, the moment of inertia decreased by a factor of 4

4 0
2 years ago
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