Answer:
The velocity of the object at the bottom is, v = 17.15 m/s
Explanation:
Given data,
The initial velocity of the object, u = 0
The height of the hill, h = 15 m
Let 'S' be the distance of the slope of the hill and 'Ф' be the slope of the hill formed with the ground.
The acceleration due to gravity component along the slope is given by,
a = g Sin Ф
The distance of the slope since height 'h' of the hill is given,
s = h / Sin Ф
Using the III equation of motion,
v² = 2 as (∵ u = 0)
v² = 2 x g Sin Ф x h / Sin Ф
= 2 gh
Therefore,
<em> v = √(2gh)</em>
Substituting the given values,
v = √(2x9.8x15)
= 17.15 m/s
Hence, the velocity of the object at the bottom is, v = 17.15 m/s
Discontinuous is not a spectra
Answer:
The number of revolutions turned by the centrifuge is 8250 revolutions.
Explanation:
Given;
number of revolution per minutes, ω = 15000 rpm
time of motion, t = 330 s = 5.5 minutes
The number of revolutions turned by the centrifuge is given by;
Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.
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