Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
4/2=2
4/3=1.33
4/4=1
4/5=0.8
4/0= undefined
Answer:
Sasha’s down payment will likely be less if she decided to buy.
Answer:
(8) 
and 
(9) 
and 
(10) 
and 
Step-by-step explanation:
Given [Missing from the question]
Required
Write a system of linear equations
The solutions to this question is open and have different solutions
Solving (8) (-6,-2)
Let the equations be: x + y and 2x - y
--- (1)
-- (2)
So, the equations are:
and
Solving (9) (-12, 18)
Let the equations be: 3x - y and 4x + y
So, the equations are:
and
Solving (9): (2,0)
Let the equations be: x + y and x - y
So, the equations are:
and
