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never [62]
4 years ago
15

200 students in a high school senior class are surveyed about what majors they intend to declare in college.

Mathematics
1 answer:
vekshin14 years ago
7 0

Answer:

2/5

1/2

3/20

3/4

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The cotangent function can be rewritten by trigonometric relations, that is:

\cot 330^{\circ} = \frac{1}{\tan 330^{\circ}} = \frac{\cos 330^{\circ}}{\sin 330^{\circ}} (1)

By taking approach the periodicity properties of the cosine and sine function (both functions have a period of 360°), we use the following equivalencies:

\sin 330^{\circ} = \sin (-30^{\circ}) = -\sin 30^{\circ} (2)

\cos 330^{\circ} = \cos (-30^{\circ}) = \cos 30^{\circ} (3)

By (2) and (3) in (1), we have following expression:

\cot 330^{\circ} = -\frac{\cos 30^{\circ}}{\sin 30^{\circ}}

If we know that \sin 30^{\circ} = \frac{1}{2} and \cos 30^{\circ} = \frac{\sqrt{3}}{2}, then the result of the trigonometric expression is:

\cot 330^{\circ} = -\frac{\frac{\sqrt{3}}{2} }{\frac{1}{2} }

\cot 330^{\circ} = -\sqrt{3}

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