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3 years ago

Can you help me find the answer quick

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

3 0

Answer: 14x+30y-20

Step-by-step explanation:

= 14(x+y)+y-20+15y

= 14x+14y+y-20+15y

= 14x+30y-20

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The radius of a circular clock is 13 centimeters. write an expression that can be used to find the circumference of the clock fa

xeze [42]

2*pi*R should be substituted in. 2*13*3 = 78

7 0

3 years ago

1. What are the domain restrictions of q^2−7q−8/q^2+3q−4

Ksju [112]

(1)

we are given

$\frac{q^2-7q-8}{q^2+3q-4}$

We know that any function is undefined when denominator =0

so, we will set denominator =0

and then we can solve for q

$q^2+3q-4=0$

now, we can factor it

$(q+4)(q-1)=0$

$(q+4)=0$

$q=-4$

$(q-1)=0$

$q=1$

so,

q≠1 and q≠−4............Answer

(2)

we are given

$\frac{y^2-3y-40}{y^2+9y+20}$

Since, any function is undefined when denominator =0

so, we set denominator =0

and then we can solve for y

$y^2+9y+20=0$

$(y+4)(y+5)=0$

$(y+4)=0$

$y=-4$

$(y+5)=0$

$y=-5$

so,

y≠−5

y≠−4.............Answer

3 0

3 years ago

Ralph sold brownies for $0.28 a piece in order to buy baseball cards. If the card cost $0.60 per pack, and if Ralph had no money

Svetradugi [14.3K]

Is there a formula for this? Or maybe do you know what equation it's used for?

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3 years ago

Suppose a car going 65 mph is traveling north parallel to a train going 50 mph. Once the front of the car is as far north as the

scoray [572]

Answer:

0.75 Miles

Step-by-step explanation:

To find the answer we have to find the difference in the distance the train and car travelled

65/60 is 1.083333 which is miles per minute then multiplied by 3 is 3.25 mile gone in 3 minutes

For the train it is 50/60 which is 0.833333 and the times 3 is 2.5 miles in three minutes

3.25 miles minus 2.5 miles is 0.75 miles so that is how long the train is

6 0

3 years ago

Using the digits 0-9, at most one time each, create five ordered pair that represent a linear

krok68 [10]

Answer:

(-9, 0), (-8, 1), (-7, 2), (-6, 3) and (-5, 4)

Step-by-step explanation:

From the graph attached,

Ordered pairs which lie on the given line (-9, 0), (0, 3), (3, 4), (6, 5) and (9, 6).

Since all the points lie on the same line, rate of change of the linear function will be defined by the slope of the given line.

Slope of the line passing through (0, 3) and (3, 4) = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{4-3}{3-0}$

$m_1$ = $\frac{1}{3}$

Now we have to find the ordered pairs which represent a linear function having slope greater than $\frac{1}{3}$ .

So the points will be (-9, 0), (-8, 1), (-7, 2), (-6, 3) and (-5, 4).

Slope of the linear function passing through (-9, 0) and (-8, 1)

$m_2$ = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{1-0}{-8+9}$

= 1

Here $m_2>m_1$

6 0

3 years ago