The correct solution is shown in the graph (D)
Given that the budget is $24 and the minimum is 7 tubs, the fourth graph shows the area in which both constraints are satisfied: triangular area between the points
7 small tubs
8 small tubs
3 large and 4 small tubs
The sixth grade runs a bake sale for 55 hours and makes $170.
So in one hour, they made 170/55 = 3.09 dollars.
Rate: $3.09/h
The seventh grade sets up a dunking booth for 44 hours and makes $112.
So in one hour, they made 112/44 = 2.54 dollars.
Rate: $2.54/h
The eight grade has a car wash and makes $192 in 66 hours.
So in one hour, they made 192/66 = 2.90 dollars.
Rate $2.90/h
3.09 > 2.90 > 2.54
So R(6th) > R(8th) > R(7th)
Which means that the sixth grade has the highest rate for raising money.
Hope this helps! :)
Answer:
-5
Step-by-step explanation:
The coefficient is the number attached to the variable.
Answer:
<em>y=-6</em>
Step-by-step explanation:
<em>Geometric Sequences</em>
Any given sequence is said to be geometric if each term 
can be obtained as the previous term 
by a constant value called the common ratio.
or equivalently
Looking closely at the sequence 2, y, 18,-54, 162 we can try to find out if it's a geometric sequence or not. We compute the possible common ratios
and we see they both result -3. If we use r=-3 and try to find the second term (y), then
y=2*(-3)=-6
Now we compute the third term: (-6)(-3)=18
Since we got the third term as given in the original sequence.
So y=-6
The solution or
the answer is x=1
