What is the product of d – 9 and 2d2 11d – 4? 2d3 – 7d2 – 103d 36 2d3 – 7d2 – 95d 36 2d3 7d2 – 95d 36 2d3 7d2 – 103d 36.

Mathematics

1 answer:

Mice21 [21]2 years ago

7 0

The product of algebraic expression is $\rm 2d^3 - 7d^2- 103d + 36$ .

We have to determine

What is the product of d - 9 and 2d^2+11d-4?

<h3>How to find the product of two algebraic expressions?</h3>

The product of the algebraic expressions is also an algebraic expression. Lastly, simplify the algebraic expression by the fundamental operations of terms for combining the like terms.

Therefore,

The product of algebraic expression is;

$\rm = (d - 9) \times (2d^2 + 11d - 4)\\\\= d (2d^2 + 11d - 4)-9 (2d^2 + 11d - 4)\\\\= 2d^3+11d^2-4d-18d^2-99d+36\\\\=2d^3 - 7d^2- 103d + 36$

Hence, the product of algebraic expression is $\rm 2d^3 - 7d^2- 103d + 36$ .

To know more about the Product click the link given below.

brainly.com/question/1337024

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