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shutvik [7]
3 years ago
8

How do you subtract to find the sum of a positive and negative integer

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

positive integer subtraction 8-9= -1

negative integer subtraction -8-(-9) but before you can subtract you have to distribute the negative sign so now your problem looks like -8+9 because a negative times a negative equals a positive and now your answer is 1

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Multiply the polynomials: (x + 3)(x2 – 5x + 12)
LekaFEV [45]

Answer:

x³ - 2x² - 3x + 36

Step-by-step explanation:

(x + 3)(x² - 5x + 12)

Each term in the second factor is multiplied by each term in the first factor , that is

x(x² - 5x + 12) + 3(x² - 5x + 12) ← distribute parenthesis

= x³ - 5x² + 12x + 3x² - 15x + 36 ← collect like terms

= x³ - 2x² - 3x + 36

3 0
3 years ago
Read 2 more answers
If p varies directly with T and p =105 when T=400.Find p when T =500
kumpel [21]

Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3>k =  \frac{21}{80}</h3>

So the formula for the variation is

<h2>p =  \frac{21}{80} T</h2>

when

T = 500

Substitute it into the above formula

That's

p =  \frac{21}{80}  \times 500

Simplify

The final answer is

<h3>p = 131.25</h3>

Hope this helps you

7 0
4 years ago
Does the table represent a function? Why or why not? X 2 3 3 4 5 y 4 5 6 7 7​
QveST [7]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Roger can run one mile in 8 minutes. jeff can run one mile in 6 minutes. if jeff gives roger a 1 minute head​ start, how long wi
Anastasy [175]
Recall your d = rt, distance = rate * time.

now, if Roger can do 1 mile in 8 minutes, so in 1 minute, he has done then 1/8 of a mile, so his rate is 1/8 miles per minute.

if Jeff can do 1 mile in 6 minutes, he's faster, in 1 minute he has done 1/6 of a mile, so his rate is 1/6 miles per minute.

now, when Jeff catches up with Roger, the distance covered by both will be the same, say "d" miles, because, at that millisecond, Jeff will be neck and neck with Roger, and their covered distance will be the same.

now, Jeff is generous and let Roger roll on for 1 minute before him, so, by the time time Roger has covered "d" miles, he has been running for say "t" minutes.

however, since Jeff started later by 1 minute, he hasn't been running for "t" minutes, but for "t - 1" minutes.

\bf \begin{array}{lccclll}&#10;&\stackrel{miles}{distance}&\stackrel{mpm}{rate}&\stackrel{minutes}{time}\\&#10;&------&------&------\\&#10;Roger&d&\frac{1}{8}&t\\\\&#10;Jeff&d&\frac{1}{6}&t-1&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;\boxed{d}=\frac{1}{8}t\\\\&#10;d=\frac{1}{6}(t-1)\\&#10;------\\&#10;\boxed{\frac{1}{8}t}=\cfrac{t-1}{6}&#10;\end{cases}&#10;\\\\\\&#10;\cfrac{t}{8}=\cfrac{t-1}{6}\implies 6t=8t-8\implies 8=2t\implies \cfrac{8}{2}=t\implies \boxed{\stackrel{mins}{4}=t}
4 0
3 years ago
the water machine at local grocery store fills a jug with 3.7 litters of water.If you fill 4 jugs how many litters of water is t
Ganezh [65]
3.7 multiplied by 4=14.8litres
8 0
3 years ago
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