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Semmy [17]
2 years ago
14

How many 1/2 foot unit cubes can be added to fill a 388 1/4 rectangular prism

Mathematics
1 answer:
miss Akunina [59]2 years ago
4 0

Answer:

The volume of the cube is 1/2 x 1/2 x 1/2 = 1/8

Step-by-step explanation:

<em>I DONT KNOW IF THIS IS THE RIGHT ANSWER
</em>

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-1/2 (-6x + 3) plz helpppp
umka21 [38]

Answer:

-1/2

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Choose the correct description of the graph of the compound inequality x − 1 less than or equal to 9 or 2x greater than or equal
DerKrebs [107]
X - 1 < = 9         or         2x > = 24
x < = 9 + 1                    x > = 24/2
x < = 10                        x > = 12

closed circle on 10, shaded to the left
closed circle on 12, shaded to the right

________10_______12__________
       <====X                 X======>
the X represents closed circles
8 0
3 years ago
What is the determinant of H=
Triss [41]

Answer:

The answer is -7

Step-by-step explanation:

I took the test! Hope this helps <3

4 0
3 years ago
Find the point on the parabola y^2 = 4x that is closest to the point (2, 8).
guapka [62]

Answer:

(4, 4)

Step-by-step explanation:

There are a couple of ways to go at this:

  1. Write an expression for the distance from a point on the parabola to the given point, then differentiate that and set the derivative to zero.
  2. Find the equation of a normal line to the parabola that goes through the given point.

1. The distance formula tells us for some point (x, y) on the parabola, the distance d satisfies ...

... d² = (x -2)² +(y -8)² . . . . . . . the y in this equation is a function of x

Differentiating with respect to x and setting dd/dx=0, we have ...

... 2d(dd/dx) = 0 = 2(x -2) +2(y -8)(dy/dx)

We can factor 2 from this to get

... 0 = x -2 +(y -8)(dy/dx)

Differentiating the parabola's equation, we find ...

... 2y(dy/dx) = 4

... dy/dx = 2/y

Substituting for x (=y²/4) and dy/dx into our derivative equation above, we get

... 0 = y²/4 -2 +(y -8)(2/y) = y²/4 -16/y

... 64 = y³ . . . . . . multiply by 4y, add 64

... 4 = y . . . . . . . . cube root

... y²/4 = 16/4 = x = 4

_____

2. The derivative above tells us the slope at point (x, y) on the parabola is ...

... dy/dx = 2/y

Then the slope of the normal line at that point is ...

... -1/(dy/dx) = -y/2

The normal line through the point (2, 8) will have equation (in point-slope form) ...

... y - 8 = (-y/2)(x -2)

Substituting for x using the equation of the parabola, we get

... y - 8 = (-y/2)(y²/4 -2)

Multiplying by 8 gives ...

... 8y -64 = -y³ +8y

... y³ = 64 . . . . subtract 8y, multiply by -1

... y = 4 . . . . . . cube root

... x = y²/4 = 4

The point on the parabola that is closest to the point (2, 8) is (4, 4).

4 0
3 years ago
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