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Ymorist [56]
4 years ago
8

What are the domain and range of f(x) = -log5(x + 2)?

Mathematics
1 answer:
siniylev [52]4 years ago
3 0

Try looking it up I'm this thing called math way

that will help a lot....

If u still need help you can ask a teacher or a friend or family member.

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Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

The exact value of cos 15°.

Solution:

$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}

Using half-angle identity:

$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}

$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}

Using the trigonometric identity: \cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}

            $=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}

Let us first solve the fraction in the numerator.

            $=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}

Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

            $=\sqrt{\frac {2+\sqrt{3}}{4}}

Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

           $=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}

5 0
4 years ago
Plz help me help me help me
exis [7]
The answer is this :) hope I helped

7 0
3 years ago
Read 2 more answers
What is the area of the shape below
Tems11 [23]

8cm, since 6 full squares and 4 halves

hope it helps...!!!

7 0
2 years ago
Sam collected six leaves to feed to his caterpillar collection if he wanted to split the leaves among seven cages how much shoul
Kazeer [188]
6÷7 is 0.857. maybe?
3 0
3 years ago
A juice drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of drink on an average. Any overfill
ozzi

Answer:

d. The average is equal to 12 ounces.

Step-by-step explanation:

In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:

H_0:\mu=12\\H_a:\mu\neq 12

The correct alternative is d. The average is equal to 12 ounces.

5 0
3 years ago
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